Quantum numbers HELP?

n is actually 3, the electrons after the 4s section in the periodic table are 3d electrons. l is 2; electrons in a d subshell have L = 2. m is also 2; for every value of L, m can be any integer from -L to L. Since this is the last 3d electron, m is going to be its highest possible value; 2. s is -1/2, it is the second electron to occupy that orbital and therefore is assigned a quantum number of 1/2. M decides what orbital from the subshell the electron will be in. S decides whether the electron will spin clockwise or counterclockwise.